SUDOKU SOLVER In 'C'

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
main()
{
int i,j,n,s;
int k,l;
int value[9][9];
int total_row[9];
int total_col[9];
printf("'enter the inputs of a soduko,and check whether its correct or not'\n");
printf("\n input no of 'rows x column' \n");
scanf("\n%d",&k);
scanf("\t%d",&l);
printf("values\n");
for(i=0;i<k;i++)
{
total_row[i]=0;
for(j=0;j<l;j++)
{
scanf("%d",&value[i][j]);
total_row[i]=total_row[i]+value[i][j];
}
}
for(j=0;j<l;j++)
{
total_col[j]=0;
for(i=0;i<k;i++)
{
total_col[j]=total_col[j]+value[i][j];
}
}
for(i=0;i<k;i++)
{
printf("\n");
for(j=0;j<l;j++)
{
printf(" \t %d ",value[i][j]);
}
}
s=((k*(k+1))/2);
for(n=0;n<k;n++)
{
if((total_col[n])!=s)
printf("\n incorrect i/p's col_%d ",n+1 );
else if((total_row[n])!=s)
printf(" incorrect i/p's row_%d ",n+1);
else if(total_row[n] && s && total_col[n])
printf("\n correct i/p for both %d row and col ",n+1);
else if(total_row[n] && s )
printf("\n correct i/p for %d row ",n+1);
else if(s && total_col[n])
printf("\n correct i/p for %d col ",n+1);
else
{
}
}
//fflush(stdin);
getch();
getch();
getch();
getch();
getch();
getch();
getch();
getch();
}
![]() |
incorrrect i/ps if given,this o/p is shown |
![]() | |||
if correct i/ps are given this o/p is shown |